The discussion centers on the normal distribution function defined as e^(-(x-μ)^2/(2 σ^2))/(sqrt(2 π) σ). Participants confirm that this function does not have a minimum value. The approach involves taking the derivative of the function and setting it to zero to find critical points, but it is emphasized that further analysis is required to distinguish between maxima and minima. The conclusion is that the normal distribution function approaches zero but never reaches a minimum value.
PREREQUISITESStudents studying statistics, mathematicians, and anyone interested in understanding the properties of the normal distribution function and its implications in statistical analysis.
What is the answer you got? And then, how do you tell the difference between a maximum and a minimum?Painguy said:I figured I'd take the derivative and set it equal to 0, but then what?