Minimum polynomial over a field

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Homework Help Overview

The discussion revolves around determining the dimension of the field extension Q(√(3 + 2√2)) over Q (the rationals). Participants are exploring the properties of the minimum polynomial associated with this extension.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the simplification of the problem by recognizing that (3 + 2√2) can be expressed as (1 + √2)². There are attempts to identify the degree of the minimum polynomial and its irreducibility. Questions arise regarding the necessity of additional details beyond irreducibility.

Discussion Status

The discussion is active, with various interpretations being explored. Some participants suggest that the degree of the extension is 2, while others question whether finding the minimum polynomial is essential for determining the extension's degree. Guidance is offered regarding the relevance of definitions and theorems in this context.

Contextual Notes

There is an indication that the participants may be working under specific homework constraints, which could limit the methods or approaches they consider. The need for clarity on the definitions and theorems related to field extensions is also noted.

math8
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The question is to determine the dimension over Q(rationals)of the extension Q(sqrt(3+2sqrt2)).
So we need to find [Q(sqrt(3+2sqrt2)): Q].

All I can say is that (3+2sqrt2) = (1+sqrt2)^2.
I also know that we're trying to find the degree of the minimum polynomial over Q that has sqrt(3+2sqrt2) as a root.

But I don't know how to proceed.
 
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I'm not really sure how to explain it, but it seems obvious to me how to go about constructing that particular field extension out of other field extensions that are very easy to understand. (And your observation makes this even more obvious)

You have a problem: you want to compute [Q(sqrt(3+2sqrt2)): Q].
You can simplify this problem.
Do so.
 
I would say that this degree is 2, and the minimum polynomial is (x^2)-2x-1.
 
My question is, are there some other details that need to be specified other than showing that (x^2)-2x-1 is irreducible?
 
You don't actually need to find the minimal polynomial of that element. You just have to find the degree of the field extension. And you already know the degree of Q(sqrt(3+2sqrt2)); it would be clear if you wrote the extension differently...

If you're not sure about the details, you can always look at the definitions and theorems! It would certainly be faster than asking for help over the internet. :wink:

But yes, the relevant theorem is:
Theorem: If f is an irreducible integer polynomial of degree d, and f(a) = 0, then [Q(a) : Q] = d.
 

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