Minimum Thickness of a film with wavelength and index of refraction.

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SUMMARY

The minimum thickness of a soap film that appears green, with an index of refraction of 1.35, can be calculated using the formula x = L(λ/2t), where λ is the wavelength of light in air (535 nm). To derive this equation incorporating the index of refraction, one must consider the effective wavelength in the medium, which is λ/n. The provided HyperPhysics link offers additional insights into optical interference relevant to this calculation.

PREREQUISITES
  • Understanding of optical interference principles
  • Familiarity with the concept of wavelength in different media
  • Basic knowledge of the index of refraction
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of optical interference equations
  • Learn about the effects of varying indices of refraction on film thickness
  • Explore the relationship between wavelength and index of refraction in different materials
  • Investigate practical applications of thin film interference in coatings and optics
USEFUL FOR

Students in physics, optical engineers, and anyone interested in the principles of light interference and thin film applications.

LadiesMan
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1. If the index of refraction of you soap was 1.35, calculate the (minimum) thickness of the film at that part of the film that appears green, given that in air, green light has a wavelength of 535 nm.



2. x = L(lambda/2t)



3. I can't figure out how to derive the equation with n (index of refraction)
 
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