Mixing two liquids with equal mass, find pressure

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Homework Statement


A mass of a liquid of density ρ is thoroughly mixed with an equal mass of another liquid of density 2ρ. No change of the total volume occurs.

Homework Equations


The Attempt at a Solution


i tried to use ρ=[tex]\frac{m}{v}[/tex]
then v=[tex]\frac{m}{\rho}[/tex]
therefore v1+v2=V
[tex]\frac{m}{\rho}[/tex]+[tex]\frac{m}{2\rho}[/tex]=v
[tex]\frac{3m}{2\rho}[/tex]=V
[tex]\frac{3m}{2V}[/tex]=[tex]\rho1[/tex]
[tex]\rho1[/tex] \ [tex]\rho[/tex]
in the end i get [tex]\rho1[/tex] = [tex]\frac{3}{2}[/tex][tex]\rho[/tex]

but i was wrong couldn't find out the reason ><
 
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Total volume V = 3m/2ρ

Total mass = 2m

So new density ρ' = 2m/V = ...?
 


oh no
!@#$%^&*()
=.=
cant think that this could be that simple ><
but anyway its the right answer
ths for solving it for me
 
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