# Mixing two liquids with equal mass, find pressure

1. May 17, 2010

### look416

1. The problem statement, all variables and given/known data
A mass of a liquid of density ρ is thoroughly mixed with an equal mass of another liquid of density 2ρ. No change of the total volume occurs.

2. Relevant equations

3. The attempt at a solution
i tried to use ρ=$$\frac{m}{v}$$
then v=$$\frac{m}{\rho}$$
therefore v1+v2=V
$$\frac{m}{\rho}$$+$$\frac{m}{2\rho}$$=v
$$\frac{3m}{2\rho}$$=V
$$\frac{3m}{2V}$$=$$\rho1$$
$$\rho1$$ \ $$\rho$$
in the end i get $$\rho1$$ = $$\frac{3}{2}$$$$\rho$$

but i was wrong couldnt find out the reason ><

2. May 17, 2010

### rl.bhat

Re: Pressure

Total volume V = 3m/2ρ

Total mass = 2m

So new density ρ' = 2m/V = ....?

3. May 17, 2010

### look416

Re: Pressure

oh no
!@#\$%^&*()
=.=
cant think that this could be that simple ><
but anyway its the right answer
ths for solving it for me

Last edited: May 17, 2010