Mixing two liquids with equal mass, find pressure

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SUMMARY

The discussion focuses on calculating the new density of a mixture formed by combining two liquids with equal masses, where one liquid has a density of ρ and the other has a density of 2ρ. The total volume remains constant, leading to the conclusion that the new density (ρ1) of the mixture is 3/2 ρ. The participant initially struggled with the calculations but ultimately confirmed the correct answer through collaborative problem-solving.

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  • Understanding of basic density formula: ρ = m/V
  • Knowledge of mass and volume relationships in mixtures
  • Familiarity with algebraic manipulation of equations
  • Concept of density in fluid mechanics
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  • Explore the concept of mixing liquids and its effects on density
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Students in physics or chemistry, educators teaching fluid mechanics, and professionals in chemical engineering or material science who need to understand liquid mixtures and density calculations.

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Homework Statement


A mass of a liquid of density ρ is thoroughly mixed with an equal mass of another liquid of density 2ρ. No change of the total volume occurs.

Homework Equations


The Attempt at a Solution


i tried to use ρ=\frac{m}{v}
then v=\frac{m}{\rho}
therefore v1+v2=V
\frac{m}{\rho}+\frac{m}{2\rho}=v
\frac{3m}{2\rho}=V
\frac{3m}{2V}=\rho1
\rho1 \ \rho
in the end i get \rho1 = \frac{3}{2}\rho

but i was wrong couldn't find out the reason ><
 
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Total volume V = 3m/2ρ

Total mass = 2m

So new density ρ' = 2m/V = ...?
 


oh no
!@#$%^&*()
=.=
cant think that this could be that simple ><
but anyway its the right answer
ths for solving it for me
 
Last edited:

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