Modelling electromagnetic wave reflection

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SUMMARY

The discussion centers on calculating the power of a reflected electromagnetic field from a radar system on a plane. The equation provided, Prx = Gtx*Grx((c/ftx)/(4*Pi*2*h))^2*gamma^2, incorporates the gains of the transmitter and receiver, the wavelength, and the reflection factor. The radius is set as 2*h because the wave travels down to the ground and back up to the receiver, effectively doubling the distance. This model follows the principles outlined in antenna theory, specifically the antenna link equation for the far-field.

PREREQUISITES
  • Understanding of electromagnetic wave propagation
  • Familiarity with antenna theory and link equations
  • Knowledge of radar systems and their operational principles
  • Basic grasp of spherical geometry in wave propagation
NEXT STEPS
  • Study the antenna link equation in detail from an antenna theory textbook
  • Explore the concept of space loss factors in electromagnetic wave propagation
  • Research the Poynting vector and its application in electromagnetic field calculations
  • Investigate the effects of reflection coefficients in radar signal analysis
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Engineers, physicists, and students involved in radar technology, electromagnetic theory, and antenna design will benefit from this discussion.

niko2000
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Hi,

I am trying to calculate the power of a reflected electromagnetic field and can't find a physical explanation for a given solution.

I've noticed the following example:

The Plane has a radar for altitude measurement which emmits the power Ptx at the frequency ftx. Calculate the power of the received waves when the plane altitude is h=60m and gamma (reflection) factor of the ground is 0.1.

The solution is Prx = Gtx*Grx((c/ftx)/(4*Pi*2*h))^2*gamma^2

What I don't understand here is why is it appropriate to take 2*h as a radius.

c/fth is the wave length
Gtx and Grx are the gains of the receiver and transmitter
and the factor (4*Pi*r)^2 in the denominator comes from spherical geometry (the sphere with radius r has a surface 4*Pi*r^2 - another 4*Pi comes from gain formula derivation)

The factor gamma is squared because the Poynting vector is a product of Electric and magnetic force and the ground reflects both thus gamma^2.

What I don't understand here is why the radius is set as 2*h.

I tried to solve the problem the following way:

The wave power at the point of collision is proportional to 1/(4*Pi*h)^2. At that point we consider the ground reflets 1/gamma^2 of the power and the reflected power at the receiving point is proportional to 1/(4*Pi*h^2).

I would appreciate if anyone could correct my point of view and explain what's the correct way to model a reflected electromagnetic wave.

Thank you!

Niko
 
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That isn't the radius, the \lambda / (4\pi r^2) factor is called the space loss factor. In the far field, the source of an electromagnetic wave appears to be like a point source, thus, there is an inherent spreading of the wave over 4\pi r^2 in the same sense as a spherical surface is spreading. r, the distance between source and receiver is taken as 2h because the wave travels h to the ground, and then another distance h back up to the receiver on the plane.

The given equation is the antenna link equation for the far-field, you will find this in any antenna textbook.
 
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