Molar Heat of Fusion experiment question?

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SUMMARY

The discussion focuses on calculating the molar heat of fusion for an unknown solid using a constant heat input of 13.1 J/s over a duration of 2.33 minutes. The total heat applied is calculated to be 1831.38 J. The key question is whether this value corresponds to the molar heat of fusion for water, which is known to be 6.01 kJ/mol. The conclusion drawn is that the unknown solid's molar heat of fusion can be determined from the heat applied, and it is not identical to that of water.

PREREQUISITES
  • Understanding of the concept of molar heat of fusion
  • Basic knowledge of heat transfer and energy calculations
  • Familiarity with unit conversions (Joules to kJ)
  • Ability to perform calculations involving time and power
NEXT STEPS
  • Calculate the molar heat of fusion for the unknown solid using the formula: Q = n * ΔH_fus
  • Research the molar heat of fusion values for various substances for comparison
  • Learn about the phase changes of matter and their associated energy changes
  • Explore the concept of specific heat capacity and its relation to heat transfer
USEFUL FOR

Chemistry students, educators, and anyone involved in thermodynamics or calorimetry experiments will benefit from reading this discussion.

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Molar Heat of Fusion experiment question?

Homework Statement



In one experiment heat was added to one mole of an unknown solid, at its normal melting point, at a constant rate of 13.1 J/s. If it took 2.33 minutes to melt all of the solid, what was the molor heat of fusion (in kJ/mol) of the unknown? Was the unknown water? Explain.


2. The attempt at a solution

13.1 J/s x (2.33 min x 60 sec) = 1831.38 J
 
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That's amount of heat, what is molar heat of fusion?

What is molar heat of fusion for water?

Are these identical?
 
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