Moment of a 2-D Force: Solving for P

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SUMMARY

The discussion focuses on calculating the moment of a 2-dimensional force of 5 units acting in the direction of the line y = 3x at the point P = (-1, -2). The moment is determined using the equation M = r × F, where r is the position vector from the origin to point P. Participants express confusion regarding the application of the force vector F and the cross product operation. The correct approach involves determining the force vector components based on the given direction and magnitude before applying the cross product to find the moment about the origin.

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  • Understanding of vector operations, specifically cross products
  • Familiarity with 2-dimensional force analysis
  • Knowledge of position vectors in Cartesian coordinates
  • Proficiency in using the moment equation M = r × F
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  • Study the properties and applications of the cross product in physics
  • Explore examples of moment calculations in 2-dimensional systems
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arsalan_y
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Homework Statement


A 2-dimensional force of 5[units] in the direction of the line y = 3x (upwards) acts through the
point P = (−1,−2). Find the moment of the force about the origin

Homework Equations



M = Fd

The Attempt at a Solution


i tried putting x = -1 and y = -2 into the y=3x but it doesn't work and i completely don't know how to do it.
 
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arsalan_y said:

Homework Statement


A 2-dimensional force of 5[units] in the direction of the line y = 3x (upwards) acts through the
point P = (−1,−2). Find the moment of the force about the origin

Homework Equations



M = Fd

The Attempt at a Solution


i tried putting x = -1 and y = -2 into the y=3x but it doesn't work and i completely don't know how to do it.

i used the quation M= r X F
where OP=r = -i -2j
then i get M = (-i - 2j) X F
i don't know what to do after that to find F
 

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