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Googl
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Hi,
I have a revision question, it's actually quite popular on the Internet but I would just like some help with it.
A metre rule is supported on a knife-edge placed at the 40 cm graduation. It is found that the metre rule balances horizontally when a mass which has a weight of 0.45 N is suspended at the 15 cm graduation, as shown in the diagram. Calculate the moment, about the knife-edge in this balanced condition, of the force due to the mass of the rule.
You can see a copy of this question in this http://books.google.co.uk/books?id=...is supported on a knife edge placed"&f=false" or search a part of the text above.
I understand that Turning moment = Force x Distance from the pivot this means...
Distance = 40 - 15 = 25cm
Force = 0.45 N
This means 25 cm x 0.45N = 11.25N?
Thanks...
I have a revision question, it's actually quite popular on the Internet but I would just like some help with it.
A metre rule is supported on a knife-edge placed at the 40 cm graduation. It is found that the metre rule balances horizontally when a mass which has a weight of 0.45 N is suspended at the 15 cm graduation, as shown in the diagram. Calculate the moment, about the knife-edge in this balanced condition, of the force due to the mass of the rule.
You can see a copy of this question in this http://books.google.co.uk/books?id=...is supported on a knife edge placed"&f=false" or search a part of the text above.
I understand that Turning moment = Force x Distance from the pivot this means...
Distance = 40 - 15 = 25cm
Force = 0.45 N
This means 25 cm x 0.45N = 11.25N?
Thanks...
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