Moment of inertia for ball rolling up a ramp.

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SUMMARY

The discussion centers on calculating the moment of inertia for a ball rolling up an incline, specifically a ball with a mass of 1.0 kg and radius of 0.20 m, which rolls without slipping. The initial speed is 10 m/s, and it reaches a maximum height of 8.0 m. The moment of inertia formula I=(2/5)mr^2 is incorrectly applied as it only applies to uniform solid spheres. The correct approach involves using the principle of conservation of energy to derive the moment of inertia for a non-uniform sphere.

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azurken
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Homework Statement


A ball with mass 1.0 kg and radius 0.20m rolls without slipping along level ground with a speed of 10 m/s. The ball then rolls up an incline reaching a maximum vertical height of 8.0 m. What is the moment of inertia of the ball? (Do not assume the ball is a uniform sphere).

m=1.0kg
r=0.20m
v=10m/s

Homework Equations


I=(2/5)mr^2


The Attempt at a Solution


Since I really have no clue on where to start this one. I guess I'll focus in on that since it's not a uniform sphere I can still assume it's a ball and use the above formula to plug it in and solve it right?

It comes out to 0.016
 
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azurken said:

Homework Equations


I=(2/5)mr^2


The Attempt at a Solution


I guess I'll focus in on that since it's not a uniform sphere I can still assume it's a ball and use the above formula to plug it in and solve it right?

No, the formula you stated is only valid for a uniform solid sphere. So, you can't assume the formula applies in this problem.

Think of a general important principle that you could use to solve this problem.
 


Conservation of energy?
 


Yes.:smile: Give it a try.
 

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