Moments Of A Couple probably just something simple.

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SUMMARY

The discussion centers on calculating the magnitude of couple forces in an X-Y plane using the equation M = Fd. The user attempts to set up the equation with a moment of 250, leading to the expression 250 = F(3/5)(sqrt(17)) - F(4/5)(9). The user seeks confirmation of their approach and clarification on the perpendicular distance between the lines of action of the forces. The focus is on ensuring the correct application of the moment equation in the context of couple forces.

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Homework Statement



http://i124.photobucket.com/albums/p27/lollipopgourmet/untitled.jpg

If the couple has a magnitude of M, determine the magnitude F of the couple forces.
Since this is an X-Y plane, I assumed the equation would simple just be M=Fd, where I know the moment, and just have to add the the the forces multiplied by their respective distances.


The Attempt at a Solution



My attempt was simple set it up like this.

M=Fd
250 = F(3/5)(sqrt(17)) - F(4/5)(9)
Mostly I just want some certification that this is either right or wrong and if it's wrong to be steered in the right direction with possibly a new answer.
 
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The moment between 2 || forces is going to be the ⊥ distance between their lines of action isn't it?

I'm not certain that's what you found.
 

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