Moments using force and distance.

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SUMMARY

The discussion focuses on calculating the moment of a 4-kN force (F) applied at point A about point O. The moment can be expressed both as a scalar and a vector quantity using the equation M = rFsin(theta), where r is the distance from point O to point A, and theta is the angle between the force and the position vector. Participants emphasize the importance of breaking the force into its x and y components to simplify calculations, ultimately leading to the formula M_o = F_x(y) + F_y(x). Additionally, the discussion addresses finding coordinates on the x- and y-axes where the moment of F is zero.

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Homework Statement



The 4-kN force F is applied at point A. Compute the
moment of F about point 0, expressing it both as a
scalar and as a vector quantity. Determine the coordinates
of the points on the x- and y-axes about which
the moment of F is zero

Homework Equations



m=fd

The Attempt at a Solution



i think that i need to find the distance from F to the origin that is perpendicular. since the moment is always perpendicular to the line of action.
 

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Yes, I think the easiest way is to break F into its x and y components, then solve for the moment about O by algebraically summing the moments produced by these component forces. Moments can be computed this way (force times perpendicular distance), but that is not the only way. Watch plus/minus signs!
 
is there a simpler way to do this. i can't get my head round it. thanks
 
weedannycool said:
is there a simpler way to do this. i can't get my head round it. thanks
You can use M=rFsintheta, where r is the magnitude of the position vector between O and A, F stars as itself, and theta is the included angle in between F and the position vector. I find it easier to break F into its x and y components, and then M_o = F_x(y) + F_y(x)
 

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