(adsbygoogle = window.adsbygoogle || []).push({}); 1. a 1kg ball traverse a frictionless tube. the ball after falling through a height of 1.2m, strikes a1.5kg ball which initially at rest. find the velocities of the two balls, if the collision is perfectly elastic. V1= -0.97m/s V2= 3.88m/s

2. i found out the initial velocity of 1kg ball

mgh = 1/2mv^2

1(9.81)1.2= 1/2(1)v^2

v= 4.85m/s

after that, i use mu+mu = mv+mv

1(4.85)+ 1.5(0)= 1v +1.5v2

after that, what should i do to get the answer???

help me....please....

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# Homework Help: Momentum and collision

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