- #1
stupif
- 99
- 1
1. a 1kg ball traverse a frictionless tube. the ball after falling through a height of 1.2m, strikes a1.5kg ball which initially at rest. find the velocities of the two balls, if the collision is perfectly elastic. V1= -0.97m/s V2= 3.88m/s
2. i found out the initial velocity of 1kg ball
mgh = 1/2mv^2
1(9.81)1.2= 1/2(1)v^2
v= 4.85m/s
after that, i use mu+mu = mv+mv
1(4.85)+ 1.5(0)= 1v +1.5v2
after that, what should i do to get the answer?
help me...please...
2. i found out the initial velocity of 1kg ball
mgh = 1/2mv^2
1(9.81)1.2= 1/2(1)v^2
v= 4.85m/s
after that, i use mu+mu = mv+mv
1(4.85)+ 1.5(0)= 1v +1.5v2
after that, what should i do to get the answer?
help me...please...