Momentum: Calculating the Forces of a Bowling Ball

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Homework Help Overview

The discussion revolves around calculating momentum and forces related to a bowling ball, specifically focusing on the momentum of the ball and the average forces exerted during its interaction with a pillow.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the momentum of a bowling ball and seeks help with applying the relevant equations to find the average forces involved. Some participants reference Newton's second law and the concept of rate of change of momentum, while others express confusion about how to apply the formulas correctly.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the concepts of momentum and force. There is a mix of understanding and confusion, particularly regarding the application of the equations and the definitions of variables involved.

Contextual Notes

There are indications of uncertainty regarding the definitions of variables in the equations, particularly the initial velocity (u) and how to incorporate them into calculations. The original poster expresses frustration with the problem, highlighting the challenges faced in understanding the concepts.

sweetpea1993
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Momentum! eww

A) what is the momentum of an 8-kg bowling bowl rolling at 2- m/s?
I got this answer which in p=16 kg times m/s

B)If the bowling bowl rolls into a pillow and stops in 0.5 sec, calculate the average force it exerts in the pillow?

C)What is the average force that the pillow exerts on the ball?

please hwlp i have no idea!
 
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Do you know Newton's 2nd law?

F=(mv-mu)/t
 
Welcome to PF!

sweetpea1993 said:
B)If the bowling bowl rolls into a pillow and stops in 0.5 sec, calculate the average force it exerts in the pillow?

C)What is the average force that the pillow exerts on the ball?

Hi sweetpea1993! Welcome to PF! :smile:

Force = rate of change of momentum. :wink:
 


hey,
yes I know this but I'm not for sure how to put the numbers into the equation..
nice names lol :)
 
sweetpea1993 said:
… I'm not for sure how to put the numbers into the equation..

?? :confused:

rate of change of momentum = change of momentum divided by time. :smile:
 


yeah... okay so (8kg times 2m/s)- what's u stand for??
grrr i have a headache
 


HEY! I figured it out... you take the 16 which converts into Newtons times sec times 0.5 which gives you 8 Newtons!
 
sweetpea1993 said:
HEY! I figured it out... you take the 16 which converts into Newtons times sec times 0.5 which gives you 8 Newtons!

(just got up :zzz: …)

No, force = change of momentum divided by time.
 

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