A Momentum Constraint in GR: ADM Formalism

Sergei65
Messages
6
Reaction score
1
Momentum constraint in GR in ADM formalism is written in the form

$$\mathcal M_i=\gamma_{ij}D_k\pi^{kj},~~~~~~~~~~(1a)$$ or equivalently

$$\mathcal M_i=D_k\pi^{k}_i,~~~~~~~~~~(1b)$$ where
##\pi^{ij}=-\gamma^{1/2}\left(K^{ij}-\gamma^{ij}K\right)~##, ##K=\gamma^{ij}K_{ij}~##, ##\gamma=\det \gamma_{ij}~## and ##D_i~## is covariant derivative. This is from DeWitt1967 parer and original ADM parer.

However, those who deal with numerical relativity uses $$\mathcal
M_i=D_jK^j_i-D_iK.~~~~~~~~~~~~~~~(2)$$

What formula is right? (they coincides only if ##\gamma## does not depend on spatial coordinates, which is evidently not the case.
 
Physics news on Phys.org
Sergei65 said:
Momentum constraint in GR in ADM formalism is written in the form

$$\mathcal M_i=\gamma_{ij}D_k\pi^{kj},~~~~~~~~~~(1a)$$ or equivalently

$$\mathcal M_i=D_k\pi^{k}_i,~~~~~~~~~~(1b)$$ where
##\pi^{ij}=-\gamma^{1/2}\left(K^{ij}-\gamma^{ij}K\right)~##, ##K=\gamma^{ij}K_{ij}~##, ##\gamma=\det \gamma_{ij}~## and ##D_i~## is covariant derivative. This is from DeWitt1967 parer and original ADM parer.

However, those who deal with numerical relativity uses $$\mathcal
M_i=D_jK^j_i-D_iK.~~~~~~~~~~~~~~~(2)$$

What formula is right? (they coincides only if ##\gamma## does not depend on spatial coordinates, which is evidently not the case.

I think the equations 1a, 1b and 2 are all same (besides a factor of ##-\sqrt{\gamma}## in equation 2). To establish the equality you need to use the fact that the intrinsic covariant derivative is (pullback) metric compatible. Also ##D_i\sqrt{\gamma}=\frac{1}{2}\sqrt{\gamma}\gamma^{ab}D_i\gamma_{ab}=0##
 
  • Like
Likes Sergei65 and Dale
Let me ask, why we could not write ##D_i\sqrt {\gamma}=\partial_i \sqrt {\gamma}\sim\gamma^{ab}\partial_i\gamma_{ab}\ne0##? I ask this because it is well known that ##d\gamma\sim\gamma^{ab}d\gamma_{ab}##, where ##d## is usual differencial. From the other hand it seems that ##D_i\gamma=\partial_i \gamma##.
 
Last edited:
Last edited:
  • Like
Likes Ravi Mohan
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Abstract The gravitational-wave signal GW250114 was observed by the two LIGO detectors with a network matched-filter signal-to-noise ratio of 80. The signal was emitted by the coalescence of two black holes with near-equal masses ## m_1=33.6_{-0.8}^{+1.2} M_{⊙} ## and ## m_2=32.2_{-1. 3}^{+0.8} M_{⊙}##, and small spins ##\chi_{1,2}\leq 0.26 ## (90% credibility) and negligible eccentricity ##e⁢\leq 0.03.## Postmerger data excluding the peak region are consistent with the dominant quadrupolar...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. The Relativator was sold by (as printed) Atomic Laboratories, Inc. 3086 Claremont Ave, Berkeley 5, California , which seems to be a division of Cenco Instruments (Central Scientific Company)... Source: https://www.physicsforums.com/insights/relativator-circular-slide-rule-simulated-with-desmos/ by @robphy
Back
Top