Momentum is conserved in a collision

AI Thread Summary
Momentum is conserved in a collision, meaning the total momentum before the collision equals the total momentum after. While individual objects may lose or gain momentum, the overall momentum of the system remains constant. This principle applies only in a closed system with multiple objects involved in the collision. For example, in an elastic collision between two objects of equal mass, one object stops while the other moves with the same velocity as the first. Understanding that momentum conservation refers to the total system clarifies the confusion surrounding individual momentum changes.
Khemical
Messages
3
Reaction score
0
Momentum is conserved in a collision so, the momentum before collision = the momentum after the collision. But i have a hard time understanding this, as P=m*v in a collision doesn't velocity decrease? And if velocity decreases so does the momentum of the object as the mass is constant. It doesn't make sense how momentum is is conserved, can someone help me please? I'm quite confused.
 
Physics news on Phys.org
Welcome to PF;
You have described the change in momentum of one object in a collision. For a collision to happen, though, there must be more than one object.

When one object in a collision loses momentum, some other object must gain it.
Conservation of momentum only applies to a closed system.
 
You are forgetting an important part. The total momentum of a system is conserved. Take this example, imaging an elastic collision where a moving object strikes a stationary object with equal mass and then the stationary object starts moving while the moving object stops moving. What happens? Well intuitively you would say that the stationary object would start moving with the same velocity as the original one, and you would be correct. For each object, their momenta certainly were not conserved before and after, but if you take the sum of their momenta, they would certainly be equal.
 
Ahh, thank you Simon And Legaldose. It all makes sense now :)
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?

Similar threads

Back
Top