Momentum transfer in a first class lever

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Discussion Overview

The discussion revolves around the concept of momentum transfer in a first-class lever system, specifically involving a seesaw arrangement with three masses. Participants explore the implications of mass and distance from the fulcrum on momentum distribution during interactions.

Discussion Character

  • Exploratory, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant describes a seesaw system with masses m1, m2, and m3, questioning the momentum distribution based on their arrangement and distances from the fulcrum.
  • Another participant suggests that the force applied to the fulcrum (m3) is influenced by the mass of m2, linking it to inertia and resistance to motion.
  • A participant expresses confusion regarding the term "momentum distribution," seeking clarification on its meaning within the context of the question.
  • Further clarification is provided that momentum distribution refers to how momentum is shared or transferred among the masses during interactions.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the definition of momentum distribution, and there is uncertainty regarding the original question posed. Multiple interpretations and clarifications are present, indicating a lack of agreement on the core concept being discussed.

Contextual Notes

There are unresolved assumptions regarding the definitions of momentum distribution and the specific dynamics of the lever system, which may affect the clarity of the discussion.

dE_logics
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We have a seesaw arrangement, a mass m3 supports the fulcrum, we have mass m2 on one end, and a mass m1 fall on the other end with velocity v.

Considering the distance between the fulcrum and m1 is d and that of m2 is r, what will be the momentum distribution?
 
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I think -

How much the force is applied to m3 depends on m2's mass, cause the reason why force is applying on m3 is cause of m2's reluctance to change in motion (or cause of inertia).
 
Last edited:
dE_logics said:
We have a seesaw arrangement, a mass m3 supports the fulcrum, we have mass m2 on one end, and a mass m1 fall on the other end with velocity v.

Considering the distance between the fulcrum and m1 is d and that of m2 is r, what will be the momentum distribution?

Hi dE_logics! :smile:

i think nobody's answering because we don't understand the question :redface:

what do you mean by the "momentum distribution"?

what is the original question? :smile:
 
Momentum distribution between m1, m2 and m3.
 
Now how can I define momentum distribution?

When 2 bodies collide momentum gets distributed...i.e they undergo momentum distribution.
 

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