Monostable Waveforms: Solutions & Resources

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Discussion Overview

The discussion revolves around the analysis and understanding of monostable waveforms, particularly in the context of a homework problem involving trigger pulses and time constants. Participants explore the conditions necessary for triggering a monostable circuit and the implications of different voltage levels on its operation.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that a negative polarity trigger pulse with an amplitude greater than 1V is required to switch the op amp output to a low state, entering a quasi-stable state.
  • Another participant questions the presence of both positive and negative trigger spikes in the provided diagram, suggesting that only negative spikes should be necessary for the circuit to respond correctly.
  • A participant expresses uncertainty regarding the calculations for span and remainder, attempting to derive the time constant for the monostable circuit.
  • Concerns are raised about the implications of setting Vref to -1V, with one participant suggesting that this would cause the monostable to continuously produce a pulse.
  • Another participant mentions that the output pulse duration is unclear and questions the accuracy of the voltage levels depicted in the drawing.

Areas of Agreement / Disagreement

Participants generally agree on the necessity of a negative trigger pulse for the monostable circuit, but there is disagreement regarding the specifics of the trigger spikes and the implications of different voltage levels. The discussion remains unresolved on several technical points, including the correct interpretation of the circuit behavior and the calculations involved.

Contextual Notes

Some participants express uncertainty about specific calculations and the interpretation of circuit diagrams, indicating potential limitations in understanding the monostable circuit's operation. The discussion also highlights the dependence on accurate definitions of terms like span and remainder.

Weaver
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Homework Statement


2017 - Q5.png
[/B]

Homework Equations


T = Time constant x ln [span/remainder]

The Attempt at a Solution



a)[/B] The trigger pulse must have a negative polarity and an amplitude greater than 1V. V+ is at 0V in the stable state. By using these conditions for a triggering pulses, it ensures that will drop V- below that of V+ and so causing the op amp output to switch low and enter the quasi-stable state

b) ***I am a little unsure for part b, but this is my attempt:***
Workings.jpg
c) ***I am unsure of span and remainder for part c but this is my attempt:***

Span= 15-(-15)
= 30
Remainder = 15-1
=14

T = (10x103 + 1x103 )(100 x 10-9) x ln(30/14)
T = 838.35us

Recovery approximately completes in 5 Time constants
=> 5 ( (10x103 + 1x103 )(100 x 10-9) )
= 5.5 msd) ***I am a little unsure for part d, but this is my attempt:***
If Vref was -1V, the V- would always be below V+ and so cause the monostable to be constantly producing a pulse.

Or is it that the circuit will responds to positive triggering pulses?


I am not very familiar with the monostable circuit. I'd appreciate any help with this question or even a link to a resource that explains the monostable circuit better. All the examples I find online seem to be a different circuit. Thanks in advance
 

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You state that a negative 1 volt trigger will start it (correct), but that is not what your picture looks like. Why do you have 2 trigger spikes (pos and neg)?

Try reading this article. It describes circuit using logic gates and transistors, but the basic operation is similar (the way the feedback temporarily holds it in one state). https://www.electronics-tutorials.ws/waveforms/monostable.html
 
scottdave said:
You state that a negative 1 volt trigger will start it (correct), but that is not what your picture looks like. Why do you have 2 trigger spikes (pos and neg)?

Thanks Scott!

I wasn't sure about that. We had trigger like that in a lab session but now in hindsight that was to show the circuit only responded to negative spikes. There only needs to be negative spikes as the positive will do nothing, given V- will still be greater than V+.

Would the graph then look like this?
New_graph.jpg


Thanks for the link as well
 

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Cn't read your drawing very well but looks like your V+ jumps from 0 to -1V and then exponentiates back to 0. The -1V is wrong, it'd be bigger than that by a factor of at least 2 ...

Duration of output pulse?

Part (d)?
 

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