Monte Carlo Integration for ∫ xdx/(2+3x)^2 with Bounds of 0 and 1

[chimath35]

Homework Statement

Perform a Monte Carlo integration of:

∫ xdx/(2+3x)^2 with the bounds of 0 and 1 on the integral

You should use 10 trials of at least 100 data pairs per trial and average the result

I guess I am supposed to generate a x and y random number between 0 and 100 and if the output of
y=x/(2+3x)^2 is equal to the y ran I count it

I really only know and have been shown how to use libre calc not sure how to do this

Homework Equations

The Attempt at a Solution

 

[mfb]

I guess I am supposed to generate a x and y random number between 0 and 100

What is between 0 and 100?

and if the output of
y=x/(2+3x)^2 is equal to the y ran I count it

It won't be equal exactly, there is a different condition (hint: you are approximating an integral).

Every spreadsheet can do that, programming languages would be better for larger samples but for just 100 data pairs it does not matter.

 

[chimath35]

okay so I pick an x value between 0 and 1 (random) and what do I pick the y value between?

 

[chimath35]

I have the actual value of the integral and I know it is a ratio of y≤x/(2+3x)^2 count as success/ of total # of trials for each x value

 

[chimath35]

Never mind, I understand the process now and have solved the problem. Thank you for the input.