What Are the Correct Equations for Solving Magnetism Problems?

  • Thread starter Thread starter shikagami
  • Start date Start date
  • Tags Tags
    Magnetism
Click For Summary
SUMMARY

The discussion centers on the correct equations for calculating the radius of a charged particle's path in a magnetic field. The problem involves a singly charged Li7 ion with a mass of 1.16x10-26 kg accelerated through a potential difference of 500 Volts in a magnetic field of 0.4 Teslas. The participant initially used the equation V=(kq)/r, which is inappropriate for this context, leading to an incorrect radius of 2.88x10-12 meters. The correct approach involves using the kinetic energy equation KE=1/2mv2 and the formula r=(mV)/(Bq), resulting in a radius of 3.44x1013 meters, confirming that the second solution is valid while the first is not.

PREREQUISITES
  • Understanding of electric potential and kinetic energy equations
  • Familiarity with the Lorentz force and motion of charged particles in magnetic fields
  • Knowledge of fundamental constants such as the Coulomb constant (k)
  • Basic principles of electromagnetism and particle physics
NEXT STEPS
  • Study the derivation and application of the Lorentz force equation
  • Learn about the motion of charged particles in magnetic fields
  • Explore the relationship between electric potential and kinetic energy in particle physics
  • Investigate the use of conservation of energy in charged particle dynamics
USEFUL FOR

This discussion is beneficial for physics students, educators, and professionals working in fields related to electromagnetism, particle physics, and engineering applications involving charged particles in magnetic fields.

shikagami
Messages
42
Reaction score
0
I'm confused if I am using the right equations to solve this problem.

P: A singly charged Li^7 ion has a mass of 1.16x10^-26kg. It is accelerated through a potential difference of 500 Volts and then enters a magnetic field of 0.4 Teslas, moving perpendicular to the field. What is the radius of its path in the magnetic field.


I had two different solutions to this problem that has to completely different answers. First, I figured I can use the equation V=(kq)/r. Then I solved for the radius. The second way is by using the volts equation: V=PE/q, which I use to solve for the potential energy. I then used this in the kinetic energy equation KE=1/2mv^2 to solve for the velocity. This velocity I then used in the equation r=(mV)/(Bq). I got 2.88x10^-12 meters for the first solution and 3.44x10^13 meters for the second solution. Which one is right is any?
 
Physics news on Phys.org
What is your understanding of V=(kq)/r? How did you use it?
 
Well... since I knew how much volts there is, I figured that it is faster to just use that formula where k is the Coulomb constant (8.99x10^9 Nm^2/C^2), then just solve for the radius. Is it possible to use this equation like that?
 
shikagami said:
Well... since I knew how much volts there is, I figured that it is faster to just use that formula where k is the Coulomb constant (8.99x10^9 Nm^2/C^2), then just solve for the radius. Is it possible to use this equation like that?

No. The r in that equation is distance from a charge q and the V is is the electric potential due to that charge. It has nothing to do with the radius of curvature of a path of a particle, and that V is for a completely dirrerent geometry than what you have.
 
So is my second solution the right one? or are they both wrong?
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 15 ·
Replies
15
Views
1K
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
12
Views
2K