MOSFET Common Source Amplifier with Source Degeneration

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The small signal voltage gain of a MOSFET common source amplifier does not collapse with increased AC input voltage; rather, it remains fairly constant as long as the signals are sinusoidal. The gain approaches the ratio of Rd/Rs, and the expression Av=(gm*Rd)/(1+gm*Rs) consists of constants. If the FET is driven into non-linear regions, the signal ceases to be classified as small. Additionally, the standard circuit does not account for gate-to-source bias voltage, which is necessary for proper operation. Understanding these principles is crucial for effective amplifier design.
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Why does the small signal voltage gain collapse as we increase the AC input voltage?


Voltage gain = Av = (output voltage) / (input voltage). Both small signal (AC).

When you draw the small signal circuit using T-Model, you can find that
Av= (gm * Rd) / (1 + gm Rs)

gm being the the trans-conductance.

Don't need an answer that says "Because the input voltage is in the denominator"
Since as we increase the input voltage, the output voltage will increase also, but not in the same ratio.


You can see the circuit here:
http://en.wikipedia.org/wiki/Common_source
 
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Why does the small signal voltage gain collapse as we increase the AC input voltage?

It doesn't. The expression Av= (gm * Rd) / (1 + gm Rs) only contains constants.

In fact, the gain gets very close to the ratio of Rd / Rs and is fairly constant as long as the signals stay sinusoidal.

Small signals mean just that. If you drive the FET into non linear regions then the signal is no longer a small signal.

The circuit in Wikipedia does not allow for any gate to source bias voltage. To do this, you need a circuit like this:
[PLAIN]http://dl.dropbox.com/u/4222062/FET%20amp%20with%20source%20R.PNG
 
Last edited by a moderator:
vk6kro said:
Why does the small signal voltage gain collapse as we increase the AC input voltage?

It doesn't. The expression Av= (gm * Rd) / (1 + gm Rs) only contains constants.

In fact, the gain gets very close to the ratio of Rd / Rs and is fairly constant as long as the signals stay sinusoidal.

Small signals mean just that. If you drive the FET into non linear regions then the signal is no longer a small signal.

The circuit in Wikipedia does not allow for any gate to source bias voltage. To do this, you need a circuit like this:
[PLAIN]http://dl.dropbox.com/u/4222062/FET%20amp%20with%20source%20R.PNG[/QUOTE]

I am just checking out the dropbox.com. Is it save? I download the program but have not run it yet, want to check with you first. What is the catch if it is free?
 
Last edited by a moderator:
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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