Motion and Forces for a block held against a wall

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Discussion Overview

The discussion revolves around a physics homework problem involving a block held against a wall by a horizontal force, examining the forces acting on the block, including friction, and calculating the resulting accelerations under various conditions. The scope includes mathematical reasoning and problem-solving related to forces and motion.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a physics problem involving a block weighing 23.0 N held against a wall by a 61 N horizontal force, with coefficients of static and kinetic friction provided.
  • Another participant emphasizes the need for the original poster to include relevant equations and their attempts at solutions to facilitate assistance.
  • Participants discuss the calculations for frictional forces and accelerations for various applied forces, noting discrepancies in the original poster's answers for specific cases.
  • One participant clarifies that the direction of friction in one case should be considered negative, leading to a calculated frictional force of -26 N, which is below the maximum friction force.
  • There is confusion regarding the assignment of positive and negative signs to forces, particularly in relation to the direction of friction and the resulting calculations.

Areas of Agreement / Disagreement

Participants express differing views on the correct signs for forces and friction, with some agreeing on the positive direction for upward forces while others question the consistency of this approach. The discussion remains unresolved regarding the correct interpretation of signs in the context of the problem.

Contextual Notes

Participants note that the correct assignment of signs for forces is crucial for accurate calculations, but there is uncertainty about when to consider friction as positive or negative. The discussion highlights the need for clarity in defining directions and forces in the problem.

maria1998
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Homework Statement



Hello, I have attached a physics problem that I solved yet some answers (in red+the first answer) are wrong and I can't find out why...

Homework Equations

upload_2016-9-14_11-48-46.png
[/B]

The Attempt at a Solution


upload_2016-9-14_11-49-24.png

[/B]
 
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Hello Maria, :welcome:

Your question is clear enough, but PF works a little different (see guidelines). The picture can serve as a problem statement, but you still need to post the relevant equations and your attempt at solution (not just the outcome). So, show what you did to calculate the numbers and we'll help you further ...
 
the problem is: In the figure, a block weighing 23.0 N is held at rest against a vertical wall by a horizontal force https://edugen.wileyplus.com/edugen/shared/assignment/test/session.quest2528958entrance1_N10036.mml?size=14&ver=1473845185939 of magnitude 61 N. The coefficient of static friction between the wall and the block is 0.55, and the coefficient of kinetic friction between them is 0.38. In six experiments, a second force https://edugen.wileyplus.com/edugen/shared/assignment/test/session.quest2528958entrance1_N1005C.mml?size=14&ver=1473845185939 is applied to the block and directed parallel to the wall with these magnitudes and directions: (a)35 N, up, (b)13 N, up, (c)49 N, up, (d)61 N, up, (e)9.0 N, down, and (f)18 N, down. In each experiment, what is the frictional force on the block, including sign? Take the direction up the wall as positive, and down the wall as negative. Next, calculate the acceleration, including sign, of the block in each case. Note that acceleration is zero if the block does not move.
(g) What is the acceleration in (a)?
(h) What is the acceleration in (b)?
(i) What is the acceleration in (c)?
(j) What is the acceleration in (d)?
(k) What is the acceleration in (e)?
(l) What is the acceleration in (f)?

I got a wrong answer for c and i here's what i did:
for the c : sum of forces=0 which means P-W-f=0 ; 49-23=26 so f=26 but it is wrong
and for the i: a=sum of forces/m and m=W/9.8 I got -27.35 but it is wrong
 
Last edited by a moderator:
I didn't intend for you to retype the whole problem statement, sorry.

The correct sign for up and down follows from b) which is counted as correct answer: + 10 N means 10 N up. Hence the cross at answer a, I assume.

What is the direction of the friction in (c) ? Which way is your f positive ?

I expect the cross at c Units to disappear once the numerical value is right ?
 
it's okay i just copy pasted it
anyway i found the right answers but i still don t understand when f is positive or negative...
 
In (b) 23 N is down, 13 N is up, so the sum is zero with 10 N up. +10 is counted correct, so up = positive in this exercise.

For (c) you would get 49 N - 23 N (down is negative) + f = 0 leaves -26 N for f. Apparently downwards. |-26| N is still below the max friction force, so -26 N should be the right answer.
 

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