1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Motion in 1D: A Tortoise & A Hare

  1. Feb 10, 2009 #1
    1. The problem statement, all variables and given/known data
    A tortoise can run with a speed of 0.10 m/s, and a hare can run 20 times as fast. In a race, they both start at the same time, but the hare stops to rest for 5.0 minutes. The tortoise wins by a shell (40 cm).
    (a) How long does the race take? (s)
    (b) What is the length of the race? (m)

    2. Relevant equations

    d= distance
    s= speed
    t= time
    subscripts;
    h=hare
    t=tortoise

    dh=sh x th
    dt=st x tt


    3. The attempt at a solution

    i have these two equations:

    dt-0.40=(20)(0.10)(t-300)

    d=0.10t

    how do i set them equal to each other
    or how do i solve them? i have no clue.....
     
  2. jcsd
  3. Feb 11, 2009 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi aznbaby! Welcome to PF! :smile:
    (shouldn't the second equation also be dt?)

    Just put the two d's equal :wink:

    which gives you t = … ? :smile:

    (though personally I'd have defined dh = (20)(0.10)(t-300), and then put dh = dt - 0.40)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Motion in 1D: A Tortoise & A Hare
Loading...