Motion problem for constant acceleration

In summary, a pedestrian running at 6.0 m/s is trying to catch a bus that is stopped at a traffic light. When the pedestrian is 16 m away, the light changes and the bus starts accelerating at 1.0 m/s2. Using the equation for displacement, the pedestrian's and bus's distances from the light can be calculated as a function of time. It can be determined whether the pedestrian catches the bus by finding a time where their displacements are equal.
  • #1
chroncile
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0

Homework Statement


A pedestrian is running at his maximum speed of 6.0 m/s trying to catch a bus that is stopped at a traffic light. When he is at 16 m from the bus, the light changes and the bus pulls away from the pedestrian with an acceleration of 1.0 m/s2.

Does the pedestrian catch the bus and, if so, how far does he have to run? (If not, what is the pedestrian's distance of the closest approach?)


Homework Equations


d = vi * t + 0.5 * a * t2


The Attempt at a Solution


I don't understand how to do it :frown:
 
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  • #2
chroncile said:

Homework Equations


d = vi * t + 0.5 * a * t2

The Attempt at a Solution


I don't understand how to do it :frown:
Show us your best try. :biggrin: What is your equation for the displacement of the bus, from the traffic light, as a function of time t? What is your equation for the pedestrian's displacement from the traffic light as a function of time t? Is there ever a real-valued, positive time t where the displacements are equal? :wink:

Hint: there's a more general equation that you might consider using, instead of the one you quoted (and don't forget the bus and the pedestrian each have their own individual velocities and accelerations):

d = di + vit + ½at2
 

1. What is constant acceleration in terms of motion?

Constant acceleration refers to the scenario where an object's velocity increases or decreases at a constant rate over time. This means that the object's speed is changing by the same amount every second.

2. How is constant acceleration different from uniform motion?

Uniform motion is when an object moves at a constant speed with no change in its velocity. Constant acceleration, on the other hand, involves a change in velocity over time.

3. What is the formula for calculating constant acceleration?

The formula for constant acceleration is: a = (vf - vi) / t, where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time interval.

4. How do you solve a motion problem for constant acceleration?

To solve a motion problem for constant acceleration, you first need to identify the known variables, such as initial and final velocities, time, and acceleration. Then, you can use the formula a = (vf - vi) / t to calculate the missing variable.

5. What are some real-life examples of constant acceleration?

Some real-life examples of constant acceleration include a car accelerating from a stop, a roller coaster going down a hill, and a person jumping into the air.

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