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Mr. H Falls from the Top of a Climbing Wall

  1. Oct 13, 2012 #1
    A 65 Kg Mr. H fell 8.0 m from the top of a climbing wall and he is going 12.52 m/s until he hits the mats. If the mats are 40 cm thick, how much force did they exert on him to prevent him from hitting the floor?

    I think you need to use the vf^2=vi^2 + 2a(df-di) formula to find the acceleration. Then use that in the Fnet= ma but the problem is eluding me.
     
  2. jcsd
  3. Oct 13, 2012 #2

    HallsofIvy

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    Since he falls at constant speed, 12.52 m/s, until he hits the mat, vi= 12.52. Since the mat prevents him from hitting hte floor, vf must be 0. di is 0 because he is just hitting the mat, df must be no larger than 40 cm= .4 m if he does not hit the floor.

    (I am taking d= 0 at the top of the mat. You could as well take di= 40 and df= 0. That will change only the sign of the acceleration.)
     
  4. Oct 13, 2012 #3
    Thank you, so is using m(a+g) right?

    65kg(15.65m/s^2 + 9.8 m/s^2) = 1654.25 N
     
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