Multiple integration + Centroid Help.

numberonenacho
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Homework Statement


Find the volume bounded by sphere rho = rt. 6 and the paraboloid z = x^2 + y^2
and locate the centroid of this region


The attempt at a solution

http://www.mathhelpforum.com/math-help/latex2/img/4deb41286077aabd94b30802f0e6a68a-1.gif

So Thats the integral that I made for this problem, but I'm having trouble integrating it. the rdr throws it off.

Please Help~! I am having some trouble.
 
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You first integrate with z, that gives you rz in the inside. Using Fubini you get (meaning evaluate the integral) r\sqrt{6-r^2} - r(r^2) and now continue with r and theta.
 
So when i evaluate it, I get -12pi rt6 as the answer.
Am I doing it wrong? I feel like I am not doing right. If you could, could I see how someone would do a problem like this? Evaluating integrals is a little confusing for me.

And then I need lots of help on the centroid part as well. Thanks~
 
Why don't you show us what you did and we can comment on it.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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