What is the centroid of a region D lying above a sphere and below a paraboloid?

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SUMMARY

The centroid of the region D, which lies above the sphere defined by the equation x² + y² + z² = 6 and below the paraboloid z = 4 - x² - y², is determined using polar coordinates. The mass integral is expressed as M = ∫∫∫ dz r dr dθ, with z ranging from √(6 - r²) to 4 - r². The intersection points for r are found to be √2 and √5, but only r = √2 is valid for this problem since it corresponds to the higher z value of 2, ensuring the centroid is correctly positioned above the sphere and below the paraboloid.

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Homework Statement



Find the centroid of the region D, lying above the sphere x2+y2+z2 and below the paraboloid z=4-x2-y2.

Homework Equations





The Attempt at a Solution



I decided it might be easier to change it to polar coordinates soo I did
M=∫∫∫ dzrdrdθ
where z goes from sqrt(6-r2) to 4-r2
θ goes from 0 to 2∏
then i thought the r would be where the two functions intersect, so i set sqrt(6-r2)=4-r2 solving for r i got my solutions came out to be sqrt2 and sqrt5, i don't know which one to use because i thought r would go from 0 to either sqrt2 or sqrt5

if some one could help me out i would really appreciate it.. thanks
solving for r i got
 
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Look at a graph. r^2+ z^2= 6 (you forgot the "6" in your origina equation but it can be deduced from what you wrote later) and z= 4- r^2 intersect twice. For r= \sqrt{2}, z= 4- 2= 2 and for r= \sqrt{5}, z= 4- 5= -1. Because the problem says "above the sphere and below the paraoloid, you want to use the higher one, r= \sqrt{2}, z= 2.
 

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