- #1
JeffNYC
- 26
- 0
I have the following problem:
find the first 3 non-zero terms in the Maclaurin series for the function:
e-x2 + Cos[x]
I know in this case, the series behave like polynomials and I have done the following. The left expression is the first 3 terms of the e portion of the problem, and the second expression is the first 3 terms of Cosx.
(1 - x2+ x4/2)(1 - x2/2 + x4/24)
this =
1 - x2/2 + x4/24 - x2 - x4/2 - x6/24 + x4 - x6/4 + x8/48
How do I know which terms are the "first 3 non-zero terms" of this series?
Thanks - the answer is attached, I just don't understand how the polynomial, after multiplied out is consolidated at the end.
Jeff
find the first 3 non-zero terms in the Maclaurin series for the function:
e-x2 + Cos[x]
I know in this case, the series behave like polynomials and I have done the following. The left expression is the first 3 terms of the e portion of the problem, and the second expression is the first 3 terms of Cosx.
(1 - x2+ x4/2)(1 - x2/2 + x4/24)
this =
1 - x2/2 + x4/24 - x2 - x4/2 - x6/24 + x4 - x6/4 + x8/48
How do I know which terms are the "first 3 non-zero terms" of this series?
Thanks - the answer is attached, I just don't understand how the polynomial, after multiplied out is consolidated at the end.
Jeff