Multiplying equations - spiral coil heat transfer

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Discussion Overview

The discussion revolves around the process of multiplying two equations related to spiral coil heat transfer, specifically focusing on understanding how to derive a third equation from the first two. The scope includes mathematical reasoning and clarification of the manipulation of equations.

Discussion Character

  • Technical explanation, Homework-related

Main Points Raised

  • One participant seeks clarification on the meaning of "multiplying equations 8 & 9" and expresses difficulty in deriving equation 10.
  • Another participant explains that the multiplication involves taking the left-hand side (LHS) of equation 8 and multiplying it by the LHS of equation 9, and similarly for the right-hand side (RHS), but admits to not understanding how to reach equation 10 from there.
  • A third participant acknowledges trying the suggested multiplication but indicates they were unsuccessful and plans to attempt it again.
  • A later reply mentions that multiplication was not ultimately necessary and that the solution required extensive manipulation instead.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the multiplication of the equations, and there is no consensus on how to derive equation 10. The discussion remains unresolved regarding the specific steps needed to achieve the desired result.

Contextual Notes

Participants do not clarify the definitions or assumptions underlying equations 8 and 9, nor do they resolve the mathematical steps involved in deriving equation 10.

luznyr
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"multiplying equations" - spiral coil heat transfer

Hi, I was wondering if anyone could explain to me what is meant in this article by "Multiplying equations 8 & 9". I have both equation 8 and equation 9 however I cannot seem to work out how to get equation 10...not sure if it's something simple I'm missing, thanks in advance.

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That means \mbox{LHS of (8)} \times \mbox{LHS of (9)} = \mbox{RHS of (8)} \times \mbox{RHS of (9)}. (Although I don't quite understand how they get from there to (10).)
 


Ok cheers, I did try that but I couldn't get it. Will have to try again, thanks :)
 


Thanks for your help, didn't end up needing to multiply them just required a lot of tedious manipulation!
 

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