Multivariable epsilon-delta proof

Click For Summary
The discussion centers on verifying the correctness of a multivariable epsilon-delta proof. The original poster expresses uncertainty about the second-to-last step, particularly regarding the strict inequality and the signs of terms involved. Participants suggest that applying the triangle inequality earlier could clarify the logic and make the proof easier to follow. There is a request for theorems related to sums and products of continuous functions to aid in the explanation. Overall, the focus is on simplifying the proof for better understanding.
nafisanazlee
Messages
20
Reaction score
2
Homework Statement
$$\lim\limits_{(x,y) \to (1,2)} (5x^3 - x^2y^2)$$
Relevant Equations
For every $$\epsilon > 0$$, we must find $$\delta > 0$$ such that whenever
$$
\sqrt{(x - 1)^2 + (y - 2)^2} < \delta
$$
it follows that
$$
| (5x^3 - x^2y^2) - 1 | < \epsilon.
$$
I have provided my solution here. I just want to be sure if it's correct or not.
 

Attachments

  • Screenshot 2025-02-22 003454.png
    Screenshot 2025-02-22 003454.png
    23.4 KB · Views: 35
Physics news on Phys.org
There is a lot going on in obtaining the second-to-last step (obtaining the line of the strict inequality).
It seems like there could be a mixture of signs of terms that need a more detailed explanation.
 
Do you have any theorems about sums and products of continuous functions that you can use?
 
I used the triangular inequality.
 
nafisanazlee said:
I used the triangular inequality.
I think we are not talking about the same line. Are you sure about the logic giving the line with the strict inequality? It's such a combination of signs and substitutions that I can not follow it. Maybe if you applied the triangle inequality before that line to break up the terms into separate absolute values it would be easier to follow.
ADDED: I'm not saying it's wrong. I just can't follow it and would like something simpler.
 
Last edited:
First, I tried to show that ##f_n## converges uniformly on ##[0,2\pi]##, which is true since ##f_n \rightarrow 0## for ##n \rightarrow \infty## and ##\sigma_n=\mathrm{sup}\left| \frac{\sin\left(\frac{n^2}{n+\frac 15}x\right)}{n^{x^2-3x+3}} \right| \leq \frac{1}{|n^{x^2-3x+3}|} \leq \frac{1}{n^{\frac 34}}\rightarrow 0##. I can't use neither Leibnitz's test nor Abel's test. For Dirichlet's test I would need to show, that ##\sin\left(\frac{n^2}{n+\frac 15}x \right)## has partialy bounded sums...