- #1

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Any help appreciated

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- I
- Thread starter NotASmurf
- Start date

- #1

- 146

- 2

Any help appreciated

- #2

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What's your domain and codomain?

- #3

- 146

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- #4

mfb

Mentor

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More context would help, but I guess there is an easier solution. Why can't you just use the set of three numbers as label? Expressed as string or whatever if the data format is an issue.

- #5

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- #6

wrobel

Science Advisor

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The sets ##\mathbb R^m## and ##\mathbb R^n## have the same cardinality for all ##m,n##

- #7

mfb

Mentor

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Your label will have to be longer than the length of a single coordinate, in a suitable format. If you have N possible values for the single coordinate, you need N

I don't see how concatenating strings would increase the time complexity of anything.

- #8

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In any case, given ##m/n## and ##m'/n'## in reduced form (meaning that ##m## and ##n## have no common divisors and ##n>0## and likewise for ##m'## and ##n'##), you can send this to ##2^m 3^n 5^{m'} 7^{n'}##.

- #9

- #10

- 146

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What's $$ m' $$ and $$n'$$?

In any case, given ##m/n## and ##m'/n'## in reduced form (meaning that ##m## and ##n## have no common divisors and ##n>0## and likewise for ##m'## and ##n'##), you can send this to ##2^m 3^n 5^{m'} 7^{n'}##.

- #11

mfb

Mentor

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It is linear in the number of vertices, which is as good as it can get.The processing required for what those strings will be processed as it will

m' and n' are the numerator and denominator of the second fraction.

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