My revised solution:b. 1c. 10d. 5e. 15

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The discussion focuses on various combinatorial problems involving three-digit numbers, coin toss outcomes, test answer sheets, and permutations versus combinations. For three-digit numbers using {1, 2, 3}, 27 repeating and 6 non-repeating combinations are calculated. A tree diagram for four coin tosses leads to different counts for tails outcomes, with a noted discrepancy in the counts for three and fewer tails. Additionally, the number of ways to answer a six-question true-or-false test is determined to be 64, while permutations are identified for phone numbers and Social Security numbers, with combinations for poker hands. The final point addresses the calculation of unique four-digit PINs without repeated digits, leading to a total of 5040.
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1. (a) How many repeating three-digit numbers can be formed using the numbers {1, 2, 3}?
(b) How many non-repeating three-digit numbers can be formed using the numbers {1, 2, 3}?

My solutions:
a. 3 x 3 x 3=27
b. 3 x 2 x 1 =6

2. (a) Construct a tree diagram for 4 tosses of a fair coin.
(b) How many ways can you get more than three tails?
(c) How many ways can you get fewer than three tails?
(d) How many ways can you get at least three tails?
(e) How many ways can you get no more than three tails?

My solutions:
b. 1
c. 12
d. 5
e. 15

3. Determine the number of possible ways to mark your answer sheet for each test:
(a) a six question true-or-false test.

My solutions:

a. 6 questions and two choices so 2 x 2 x 2 x 2 x 2 x 2= 64

6. Decide whether a permuation or a combination is needed:
(a) a telephone number
(b) a Social Security number
(c) a hand of cards in poker
(d) the combination on a student gym locker

My solutions:
a. permutation
b. permutation
c. combination
d. permutation

7. How many different ways could first, second, and third place finishers occur in a race with
12 runners competing?

My solution: 1st 2nd 3rd, 12 runners
(12
3 ) = 220 ways
n!/k! (n-k)!

8. An ATM requires a four-digit PIN number using the digits 0-9. How many such PINs
have no repeated digits?

My solution:
nPk= n!/n-k
10 numbers, 4 digits
(10
4)= 5040
 
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Hm, seems you might need to check 2c: there are sixteen possible outcomes; four different ways to have three tails, and one possible way to have four tails. Right?

I mean, clearly 2c + 2d = 16, so one of those answers must be wrong.
 
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