Natural frequency of oscillating electron

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SUMMARY

The discussion focuses on calculating the natural frequency of an oscillating electron emitting light at a wavelength of 510nm, modeled as a lightly damped simple harmonic oscillator with a Q value of 3 x 107. The natural frequency (ω0) can be derived from the relationship between the Q value and the damping coefficient (γ). The width of the resonance is determined using the formula 2γω0, necessitating the calculation of γ for the electron, which is defined as b/m, where b is the damping coefficient and m is the mass of the electron.

PREREQUISITES
  • Understanding of simple harmonic motion and oscillators
  • Familiarity with the concept of quality factor (Q value)
  • Knowledge of damping coefficients in oscillatory systems
  • Basic principles of quantum mechanics related to electron behavior
NEXT STEPS
  • Research the calculation of natural frequency in damped harmonic oscillators
  • Study the relationship between Q value and damping coefficient (γ)
  • Explore the mass of an electron and its implications in oscillatory systems
  • Investigate resonance width and its significance in physical systems
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Students and professionals in physics, particularly those studying quantum mechanics and oscillatory systems, as well as educators preparing materials on harmonic motion and resonance phenomena.

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Homework Statement



a) Light of wavelength 510nm is emitted by an electron in an atom behaving as a lightly damped simple harmonic oscillator with a Q value of 3 x 107. Find the natural frequency of the system.

b) Find the width of the resonance.

Homework Equations



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The Attempt at a Solution



Knowing the Q value means that I need to know γ in order to get ω0. Gamma is b/m and m can be found in tables, but what is b for an oscillating electron?
 
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For part b, I know that the width of the resonance is 2γω0, but again, what is gamma for an oscillating electron?
 

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