The discussion centers on differentiating the function f(x) = 1/ln(10-x). The correct derivative is f'(x) = -1/((10-x)(ln(10-x))^2). The user initially miscalculated the derivative but received clarification that their approach was fundamentally correct, with minor errors in notation. The final expression accurately reflects the differentiation process involving the chain rule and the properties of logarithmic functions.
PREREQUISITESStudents studying calculus, particularly those focusing on differentiation techniques, as well as educators seeking to clarify concepts related to logarithmic functions.
Except for the above missing parentheses and exponentiation symbol, it is correct.SYoungblood said:Homework Statement
f(x) = 1/ln (10-x) -- I would assume it to be a fairly simple equation, but I am screwing it upHomework Equations
What is f'(x)?The Attempt at a Solution
f'(x) = (ln (10-x))^-1
= -(ln (10-x))^-2 * -1 * 1/(10-x) -- 2 negatives cancel out
= 1/((10-x) (ln(10-x))^2) -- This is as far as I got and I just can tell it isn't correct.
Thank you in advance for all help.