Natural log (ln x) derivative question

SteveM19
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Homework Statement



This is to help out a 40something calc student -- thank you all in advance for your help


Homework Equations



If f (y) = ln ln ln x, what is ∂y/∂x?

The Attempt at a Solution



I came up with 1/x, which I got by applying ∂y/∂x ln x = 1/x three times, is this right? Thank you again for your help.
 
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Is that a ##f(y)##? Or like ##f(x) = y =~ ...##
 
BloodyFrozen said:
Is that a ##f(y)##? Or like ##f(x) = y =~ ...##

I might have used the terminology incorrectly --

y = ln ln ln x

What is y prime?
 
SteveM19 said:

Homework Statement



This is to help out a 40something calc student -- thank you all in advance for your help

Homework Equations



If f (y) = ln ln ln x, what is ∂y/∂x?
As BloodyFrozen already noted, that should be f(x) = ...

Also, the problem should be asking for dy/dx, not ∂y/∂x, which is the partial derivative of y with respect to x. Unless I'm missing something, you want the ordinary derivative, dy/dx.
SteveM19 said:

The Attempt at a Solution



I came up with 1/x, which I got by applying ∂y/∂x ln x = 1/x three times, is this right? Thank you again for your help.
No, it's not right. You have a composite function, y = ln(ln(ln(x))), so you need to use the chain rule a couple of times. It also might be helpful to include parentheses as I did.In response to your other question, you can take y' to be a synonym of dy/dx.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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