Natural Logarithm of Convolution

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SUMMARY

The discussion centers on the properties of logarithms in relation to the convolution of functions. Specifically, it addresses whether the equation ln(x*y) = ln(x) + ln(y) holds true when x and y are functions undergoing convolution. The consensus is that this equation does not apply, as convolution operates on functions rather than simple variables, resulting in another function rather than a product of two variables. The realization that convolution is an integral operation clarifies the misunderstanding.

PREREQUISITES
  • Understanding of convolution operations in functional analysis
  • Familiarity with properties of logarithms
  • Basic knowledge of integrals and their applications
  • Concept of functions in mathematical contexts
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  • Study the properties of convolution in functional analysis
  • Explore the relationship between logarithmic functions and integrals
  • Learn about the applications of convolution in signal processing
  • Investigate advanced topics in functional transformations
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Mathematicians, students of calculus, and professionals in signal processing or functional analysis who seek to deepen their understanding of convolution and logarithmic properties.

tramar
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If I have a convolution of two variables, say x * y, and I take the natural logarithm of this operation, ln(x*y), do the same properties of logarithms apply?

So, does ln(x*y) = ln(x)+ln(y) ?
 
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In your notation, what are x, y, x*y and ln? Usually ln(x) is the natural log of a number (x).
 
tramar said:
If I have a convolution of two variables, say x * y, and I take the natural logarithm of this operation, ln(x*y), do the same properties of logarithms apply?

So, does ln(x*y) = ln(x)+ln(y) ?

I'm afraid your question doesn't make any sense as stated. The convolution operation is an operation on two functions, not two variables, and it gives another function. And if you ask the same question for functions, the answer is no.
 
Last edited:
I realize that now since a convolution is an integral... just wishful thinking on my part I guess.
 

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