Natural Logs and inverse functions

[b200w]

Homework Statement

Find the inverse equation (i.e. solve for x)
y=(e^x)/(1+2e^x)2. The attempt at a solution
e^x = y(1+2e^x)
x = ln(y) + ln(1+2e^x)
?
Profit!

I can't figure out what to do with ln(1+2e^x) to get the x out of there so I can finish isolating x. I tried balancing it another way and ended up with x = ln(e^x - y) - ln(2y) which as far as I can tell is worse. Any suggestions? As far as I can tell I'm probably just missing something obvious but I've been sitting here for a while trying to figure it out...

 

[Mark44]

Starting with y = e^x/(1 + 2e^x),
multiply both sides by (1 + 2e^x).

Get all the terms that involve e^x on one side, and all other terms on the other side.
Factor e^x out of the terms that have this factor and divide both sides by the factor that isn't e^x.

 

[b200w]

*facepalm* Thank you... I don't know why I couldn't figure that out...