- #1

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[-b^3-2abc +or- sqrt(b^6-12a^2b^2c^2-16a^3c^3)]/(2ab^2+4a^2c).

please i want to know if it works for all.

- Thread starter abia ubong
- Start date

- #1

- 70

- 0

[-b^3-2abc +or- sqrt(b^6-12a^2b^2c^2-16a^3c^3)]/(2ab^2+4a^2c).

please i want to know if it works for all.

- #2

- 13,001

- 550

[tex] \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{-b^{3}-2abc\pm\sqrt{b^{6}-12a^{2}b^{2}c^{2}-16a^{3}c^{3}}}{2ab^{2}+4a^{2}c} [/tex]

...?There's only one way to find out:CROSS MULTIPLY...

Daniel.

- #3

- 137

- 0

looks like the multiplication of both the nominator and the denominator by

[tex] b^{2}+2ac} [/tex]

[tex] b^{2}+2ac} [/tex]

- #4

- 574

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regardless of if it works or not the form on the right is highly useless.

- #5

- 70

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thae was a hard thing 2 say

- #6

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Daniel.

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