MHB Need extra calculus practice? Check out my worksheets

  • Thread starter Thread starter Chris L T521
  • Start date Start date
  • Tags Tags
    Calculus
Click For Summary
A TA for MATH 19A at UC-Santa Cruz is offering additional calculus practice worksheets for students seeking extra help. Constructive feedback on the worksheets is welcomed, and solutions for the first three worksheets are available upon request. The TA plans to distribute a fourth worksheet soon. Participants in the discussion praise the quality of the worksheets and express enthusiasm for the additional practice. Engaging with these resources can significantly enhance calculus understanding.
Chris L T521
Gold Member
MHB
Messages
913
Reaction score
0
Hey everyone,

I'm currently a TA for MATH 19A (Calculus I) at UC-Santa Cruz this quarter, and I make up worksheets for my sections every week. If you want to have additional practice in addition to your weekly assignments, feel free to check out my worksheets.

If you have constructive criticism on how I can improve these for my students, let met know here or through PM. (Bigsmile)

Also, I have solutions written up for worksheets 1-3 (I'm giving out worksheet 4 tomorrow in section, so I don't have them written up yet); I don't want to post those right now (because that would spoil the fun of doing the problems ;) ), but if you want them, shoot me a PM and I'll send them to you.

Enjoy!
 

Attachments

Last edited:
Physics news on Phys.org
Thank you for sharing this Chris...and to any calculus students out there, you will benefit greatly by working these examples! Kudos, Chris! :cool:
 
just curious what did you use to create these PDF's

certainly one of the better worksheets I've seen
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
4K
  • · Replies 45 ·
2
Replies
45
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K