- #1
- 4
- 0
Hello all, first post here to physics forums and I have a lot to learn. I will be attending a northern Ontario university for Mechanical Engineering in fall so hopefully this relationship proves fruitful.
Here is my problem, I bought a new stereo for my jeep.. and I am having trouble designing a closed baffle enclosure for my 10.1'' subwoofer.
Here is where I am and how I got there, and why I am having trouble...
Given:
Fs = resonant frequency = 33.5 Hz
Cms = mechanical compliance = 0.0002m/N (metres / Newton)
Sd = effective area of cone = 0.0415m^2 (metres squared)
Unknown:
Cas = Acoustic Driver Compliance Cas=Cms*Sd^2
Cab = Acoustic Box Compliance Cab=Cas *R\
R= driver to box compliance ratio
R = 2
So: Cas = 0.0002m*(0.0415m^2)^2
=0.0002m/N*(0.00172225m^4)
Cas = 3.4 * 10 ^-7 m^5/N
Therefore Cab = 3.4 * 10 ^-7 m^5/N divided by two
= 1.72 x 10^-7m5/N
Now Volume of the Box Vb = Cab *Gamma Constant (Lets assume it is 5.77)
Vb = 1.72 x 10^-7 m^5 /N * 5,77
Vb = approx .99 x 10^-7m5/N
^^^^NOW HERE IS MY ISSUE^^^^
How the hell am I coming up with such a wrong answer, surly area is not expressed in terms of M^5/Newton and why is my volume so high? The Manufacturer recommends an enclosure from 0.08 m^2
please HELP, I will greatly appreciate it and contribute as much as I can to this forum :)
Also I am fresh out of high school took a year off, and its been 2 years since high level Math or Physics courses so please excuse me if the mistake I am making is pity.
Here is my problem, I bought a new stereo for my jeep.. and I am having trouble designing a closed baffle enclosure for my 10.1'' subwoofer.
Here is where I am and how I got there, and why I am having trouble...
Given:
Fs = resonant frequency = 33.5 Hz
Cms = mechanical compliance = 0.0002m/N (metres / Newton)
Sd = effective area of cone = 0.0415m^2 (metres squared)
Unknown:
Cas = Acoustic Driver Compliance Cas=Cms*Sd^2
Cab = Acoustic Box Compliance Cab=Cas *R\
R= driver to box compliance ratio
R = 2
So: Cas = 0.0002m*(0.0415m^2)^2
=0.0002m/N*(0.00172225m^4)
Cas = 3.4 * 10 ^-7 m^5/N
Therefore Cab = 3.4 * 10 ^-7 m^5/N divided by two
= 1.72 x 10^-7m5/N
Now Volume of the Box Vb = Cab *Gamma Constant (Lets assume it is 5.77)
Vb = 1.72 x 10^-7 m^5 /N * 5,77
Vb = approx .99 x 10^-7m5/N
^^^^NOW HERE IS MY ISSUE^^^^
How the hell am I coming up with such a wrong answer, surly area is not expressed in terms of M^5/Newton and why is my volume so high? The Manufacturer recommends an enclosure from 0.08 m^2
please HELP, I will greatly appreciate it and contribute as much as I can to this forum :)
Also I am fresh out of high school took a year off, and its been 2 years since high level Math or Physics courses so please excuse me if the mistake I am making is pity.