Need help finding equation of a plane

  • Thread starter sk_88
  • Start date
  • Tags
    Plane
In summary, the equation of a plane is a mathematical representation of a flat, two-dimensional surface in a three-dimensional space. It can be written in the form of Ax + By + Cz + D = 0, and can also be used to find the distance between a point and the plane. The equation of a plane can also be written in vector and parametric forms. The normal vector of a plane is a vector that is perpendicular to the plane and points outward from the plane. To find the equation of a plane given three points, you can use the steps of finding two vectors that lie in the plane, taking their cross product to find the normal vector, and using it along with one of the three points to form the equation
  • #1
sk_88
3
0
Hi,

So my question is:

Find the equation of the plane which contains the point (0,1,3) and the line:

(x,y,z) = (-1,0,-2) + t(1,-3,-1)

Hope you guys can help me out with this, thanks A LOT!
 
Physics news on Phys.org
  • #2
Sorry, I forgot to add something else, it has to be in the form Ax+By+Cx=D. D has to be positive
 
  • #3
Please don't post the same question in more than one part of the forum.

The homework section is certainly the right place for your thread.
 

What is the equation of a plane?

The equation of a plane is a mathematical representation of a flat, two-dimensional surface in a three-dimensional space. It is typically written in the form of Ax + By + Cz + D = 0, where A, B, and C are the coefficients of the x, y, and z variables and D is a constant term.

How do I find the equation of a plane given three points?

To find the equation of a plane given three points, you can use the following steps:

1. Find two vectors that lie in the plane by subtracting the coordinates of the second point from the first point and the third point from the first point.

2. Take the cross product of these two vectors to find the normal vector to the plane.

3. Use the normal vector and one of the three points to form the equation of the plane in the form Ax + By + Cz + D = 0.

What is the normal vector of a plane?

The normal vector of a plane is a vector that is perpendicular to the plane and points outward from the plane. It is often denoted as n = (A, B, C) in the equation of a plane, where A, B, and C are the coefficients of the x, y, and z variables.

Can the equation of a plane be written in different forms?

Yes, the equation of a plane can also be written in vector and parametric forms. In vector form, it is written as r = r0 + s*v + t*w, where r0 is a point on the plane, v and w are vectors parallel to the plane, and s and t are parameters. In parametric form, it is written as x = x0 + as + bt, y = y0 + cs + dt, z = z0 + es + ft, where x0, y0, and z0 are the coordinates of a point on the plane, and a, b, c, d, e, and f are parameters.

Can the equation of a plane be used to find the distance between a point and the plane?

Yes, the distance d between a point (x0, y0, z0) and the plane Ax + By + Cz + D = 0 can be found using the formula d = |Ax0 + By0 + Cz0 + D| / √(A2 + B2 + C2).

Similar threads

  • Linear and Abstract Algebra
Replies
10
Views
1K
  • Linear and Abstract Algebra
Replies
3
Views
301
  • Linear and Abstract Algebra
Replies
3
Views
1K
  • Linear and Abstract Algebra
Replies
1
Views
1K
  • Linear and Abstract Algebra
Replies
17
Views
3K
  • Linear and Abstract Algebra
Replies
9
Views
750
  • Linear and Abstract Algebra
Replies
2
Views
1K
  • Linear and Abstract Algebra
Replies
13
Views
518
  • Linear and Abstract Algebra
Replies
2
Views
959
Replies
2
Views
782
Back
Top