Need help finding flux across a surface

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The discussion focuses on finding the upward flux across the surface defined by z = x for the vector field F = (y, -x, 0). Participants address the challenges of parameterizing the surface correctly, with suggestions for the appropriate parametrization and normal vector calculation. The importance of establishing bounds for the surface to avoid integrating over an infinite plane is emphasized. Additionally, the method for calculating the differential area element dS using the cross product of the parameterization vectors is highlighted. The conversation concludes with a reminder that simplifying the notation can streamline the integration process.
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Homework Statement



Find the upward flux across the surface z = x of the vector field F=(y,-x,0).

Homework Equations



∫∫(F\bulletn)ds

The Attempt at a Solution



I know what to do once I parametrize z = x but I am stuck on the parametrization. Would it just be: r(x,y) = (zi + j + xk) ?
 
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or could I say f(x,y,z) = z - x

so the normal vector would be : \nablaf / ||\nablaf||

= -i + k / \sqrt{}-12+12
 
The first thing you are going to have to do is put bounds on your surface. You don't want to integrate across the entire infinite plane, do you?

As far as the parameterization of the surface is concerned, it is r(x, y)= xi+ yj+ xk. You are missing the "y" but I suspect that was a typo.

The best way to find n, or better, \vec{n} dS= d\vec{S}, is to find the "fundamental vector product" of the surface. That is the cross product \vec{r}_x\times\vec{r}_y.

d\vec{S}= (\vec{r}_x\times\vec{r}_y)dxdy

I personally don't like the notation \vec{n}dS because if you take that literally, as you have here, you have to divide by the length of the normal vector to find \vec{n} and then multiply by it to find dS- and, of course, those will cancel!
 
So then it's just the double integral of the vector field dot that cross product and I just need to find the limits of integration. Thanks!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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