Need Help finding Instantaenous Velocity

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The discussion focuses on finding the instantaneous velocity of a truck rolling down a ramp described by the position function s(x) = 3x^3 + 2x^2 + 4. To determine the instantaneous velocity at x = 4 seconds, one must compute the derivative of the position function, which represents the velocity function. Evaluating this derivative at x = 4 provides the required instantaneous velocity.

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Truck rolls down a Ramp at s(x)=3X^3 + 2x^2 + 4
I need to find Instantaneous velocity at x=4 seconds... The intervals are between 0<x<4. I can't think of the answer.. I know that I'm supposed to get the derivative of it, but then I'm unsure of what to do with that..
 
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Surely, since you refer to the derivative, you know that the derivative is the derivative of the position function with respect to time. Since you are asked for the instantaneous velocity at x= 4 you evaluate the derivative function at x= 4.
 

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