Need help finding voltage across a capacitor in an RC circuit?

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SUMMARY

The discussion focuses on calculating the voltage across a capacitor in an RC circuit using the equation VC = V0(1 - e^(-t/τ)), where τ = RC and V0 is the initial voltage. The user expresses confusion regarding the differential equations involved, specifically dV/dt = (1/RC)(V) and the relationships between voltage, current, and charge. It is established that the voltage across the capacitor decays exponentially over time, governed by the time constant τ, which is the product of resistance (R) and capacitance (C).

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  • Understanding of RC circuits and their components
  • Familiarity with differential equations
  • Knowledge of exponential decay functions
  • Basic concepts of voltage, current, and charge relationships
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1. Homework Statement

Find the voltage across a capacitor in an RC Circuit, using [V]_{}[/c] (0) = 1, [V]_{}[/i] n(t)=t.

2. Homework Equations
dV/dt = (1/RC)(V)=(1/RC)([V]_{}[/in])


3. The Attempt at a Solution
New to this site: I honestly don't know where to start. Done well in Calculus. Feel DifEq is like a breed of its own..aha

I know you have to use this type of an equation: VC = V0(1− e−t /τ ) where τ = RC and V0 is the initial voltage
 
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I'm a little confused by your equations..

In general the voltage across a series RC circuit will decay exponentially, on a time constant determined by the value of RC.

The voltage across a resistor is:

[tex]V_R = IR = R\frac{dQ}{dt}[/tex]

The voltage across a capacitor is:

[tex]V_C = Q/C[/tex]

Knowing this, you should be able to set up a simple differential equation which will provide the answer you desire.
 

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