Need help in Electric Flux within a cube with Gauss' Law

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SUMMARY

The discussion focuses on calculating electric flux through a cube using Gauss' Law, specifically the equation φ = ∫E * dA. The electric field is defined as E = -5x * E0/L i + 3z * E0/L k. Participants clarify that one cannot simply substitute L for the variables x and z; instead, integration must be performed over the defined area to accurately compute the flux for each side of the cube. The correct approach involves evaluating the electric field at specific points and integrating over the respective surfaces.

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Homework Statement


I need help in figuring out if I have done this problem correctly. From what I understand ∫E * dA = E*A, where E is the electric field and A is the area of a side. My biggest concern is if I can plug in the length "L" for the "x" and "z" variables within "E = -5x * E0/L i + 3z * E0/L k" to get the electric flux of each side since I assume that "L" is the value of those two variable.

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Given: [ε0, L]

Unknown: [Electric flux of the top, bottom, front, back, left, right side, and the total]

Homework Equations


Electric Flux: φ = ∫E * dA
E = -5x * E0/L i + 3z * E0/L k

The Attempt at a Solution


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My biggest concern is if I can plug in the length "L" for the "x" and "z" variables within "E = -5x * E0/L i + 3z * E0/L k" to get the electric flux of each side since I assume that "L" is the value of those two variable.
It would not be appropriate to set x=L and z=L ... that is not what that equation means.
The equation ##\vec E(x,y,z) = \frac{E_0}{L}\left[-5x\hat\imath +3z\hat k \right]## tells you the value of ##\vec E## at different x,y,z positions in space.
So the value of ##\vec E## at x=0 and z=0 is different from that at x=0 and z=L. That is why you had to do an integral.
However, the geometry in this problem is simple enough that you will always be setting one variable to 0 or L and the flux only depends on one of the other variables.

You proceed by picking a side, then defining a small area on that side and working out the flux through that area in terms of the position.
Then you add up the flux through all the small areas that make up that side of the cube.
ie for the side in the x-y plane: 0<x<L, 0<y<L, z=0
##d\vec A = -\hat k dxdy## is the area element between x and x+dx and y and y+dy.
The flux through that area is ##d\phi = -\vec E(x,y,0)\cdot \hat k\; dxdy## ... and the total flux is given by the integral.
For this surface, the only non-zero flux is parallel to the surface (there is no flux through the surface).
... it kinda looks like this is what you are doing but I figured I'd better check.

Understanding that it is the flux through a side that counts, you can shortcut the process considerably ... ie, there is no component in the y direction so the flux through surfaces parallel to the x-z plane is zero.
No further maths needed.
 
Last edited:
Simon Bridge said:
It would not be appropriate to set x=L and z=L ... that is not what that equation means.
The equation ##\vec E(x,y,z) = \frac{E_0}{L}\left[-5x\hat\imath +3z\hat k \right]## tells you the value of ##\vec E## at different x,y,z positions in space.
So the value of ##\vec E## at x=0 and z=0 is different from that at x=0 and z=L. That is why you had to do an integral.
However, the geometry in this problem is simple enough that you will always be setting one variable to 0 or L and the flux only depends on one of the other variables.

You proceed by picking a side, then defining a small area on that side and working out the flux through that area in terms of the position.
Then you add up the flux through all the small areas that make up that side of the cube.
ie for the side in the x-y plane: 0<x<L, 0<y<L, z=0
##d\vec A = -\hat k dxdy## is the area element between x and x+dx and y and y+dy.
The flux through that area is ##d\phi = -\vec E(x,y,0)\cdot \hat k\; dxdy## ... and the total flux is given by the integral.
For this surface, the only non-zero flux is parallel to the surface (there is no flux through the surface).
... it kinda looks like this is what you are doing but I figured I'd better check.

Understanding that it is the flux through a side that counts, you can shortcut the process considerably ... ie, there is no component in the y direction so the flux through surfaces parallel to the x-z plane is zero.
No further maths needed.

Thank you, I will keep in mind to integrate the variables of dA and to be mindful of the upper and lower bounds of each problem.
However to clear things up, let's say if I were to re-do the φTop, would it equal to:

Etop = -5x E0/L i + 3z E0/L k
= -5x E0/L *(|i| |k| cos(90°)) + 3z E0/L * (|k| |k| cos(0°))
= 3 E0/L * ∫ z dz
= 3 E0/L * z2/2 | z = L, z = 0
= 3 E0 * L/2
?
Therefore, in its whole form it looks like this:
Etop = -5 E0/L * (0) * ∫ x dx + 3z E0/L * (1) * ∫ z dz ?

Meaning my original answer of φTop = 3E0L2 is incorrect?
 
Last edited:

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