Need help quik with this differentiation

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Homework Statement



attachment.php?attachmentid=64516&stc=1&d=1386241299.png


Homework Equations


[itex]\frac{d}{dx}[/itex]

attachment.php?attachmentid=64517&stc=1&d=1386241299.png


attachment.php?attachmentid=64518&stc=1&d=1386241299.png

The Attempt at a Solution



i couldn't do it because we didnt learn this type of question
 

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hi houssamxd! :smile:

(is the question to find dy/dx? :confused:)

why can't you just use the first of your "relevant equations"?
 
houssamxd said:

Homework Statement



attachment.php?attachmentid=64516&stc=1&d=1386241299.png


Homework Equations


[itex]\frac{d}{dx}[/itex]

attachment.php?attachmentid=64517&stc=1&d=1386241299.png


attachment.php?attachmentid=64518&stc=1&d=1386241299.png

The Attempt at a Solution



i couldn't do it because we didnt learn this type of question
$$\text{Let}~ G(x) = \int_0^x (t^3 + 1)^{10}dt$$

Then y = [G(x)]3

How would you find dy/dx?
 
So your question is to find the derivative [itex]d u^3/dx[/itex] where [itex]u= \int_a^x f(t)dt[/itex]?

Surely, you have learned the chain rule:
[tex]\frac{dy}{dx}= \frac{dy}{du}\frac{du}{dx}[/tex]

And to find du/dx, you need the "Fundamental Theorem of Calculus" which you give as a "relevant equation".