Need help simplifying units of slope for an angular acceleration vs torque graph

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SUMMARY

The discussion centers on simplifying the units of slope for a graph plotting angular acceleration (α) against torque (τ). The relationship is defined by the equation τ = Iα, where I represents the moment of inertia calculated as I = mr². The units of angular acceleration are confirmed to be s⁻², while mass (m) is a critical component in the calculations. The user seeks clarity on expressing torque and angular acceleration in terms of kilograms (kg), meters (m), and seconds (s).

PREREQUISITES
  • Understanding of angular acceleration (α) and its units
  • Familiarity with torque (τ) and its relationship to angular motion
  • Knowledge of moment of inertia (I) and its calculation (I = mr²)
  • Basic grasp of unit analysis in physics
NEXT STEPS
  • Research the derivation of torque (τ) in terms of kg, m, and s
  • Study the relationship between angular acceleration (α) and linear acceleration
  • Explore the concept of moment of inertia (I) in different geometries
  • Learn about unit conversion techniques in physics
USEFUL FOR

Students in physics or engineering courses, educators teaching dynamics, and anyone involved in analyzing rotational motion and torque relationships.

pentwaterwave
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In a lab we conducted in class we graphed angular acceleration vs torque, and found a positive linear correlation-easy enough. However I am getting rather stuck in simplifying the units of slope in terms of Kg, m, and s... I am fairly sure this will give me that angular acceleration equals torque times inertia but I have trouble with simplifying the slope AND with even getting torque and angular acceleration simplified to kg m and s. I would really appreciate some help! thanks!
 
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sorry pal, inertia is not a quantity, but inertial mass is.

τ=Iα

I=mr^{2}

α=\frac{d^{2}θ}{dt^{2}}

And the units of α is s^-2. m stands for mass.
 

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