- #1

Checkfate

- 149

- 0

I figured out the answer to the question I originally posted in this thread, but, I have another.

I am trying to solve [tex]2+x^{\frac{-3}{2}}>0[/tex]

I end up with [tex]x>(-2)^{\frac{-2}{3}}[/tex] by just putting the 2 on the other side and solving. This is not the right answer though... what am I doing wrong? Thanks

Thats a 2+x^(-3/2) btw. (for the top tex) and a (-2)^(-2/3) for the bottom tex.

I am trying to solve [tex]2+x^{\frac{-3}{2}}>0[/tex]

I end up with [tex]x>(-2)^{\frac{-2}{3}}[/tex] by just putting the 2 on the other side and solving. This is not the right answer though... what am I doing wrong? Thanks

Thats a 2+x^(-3/2) btw. (for the top tex) and a (-2)^(-2/3) for the bottom tex.

Last edited: