Need help solving definite integral

Click For Summary

Homework Help Overview

The discussion revolves around evaluating the definite integral of the function \(\int_0^{100} \sqrt{x} \ln{x} \, dx\). Participants are exploring the challenges posed by the behavior of the integrand at the lower limit of integration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts integration by parts but encounters difficulties due to the undefined nature of \(\ln(0)\). Other participants suggest considering limits and alternative approaches to handle the behavior of the integrand as \(x\) approaches zero.

Discussion Status

Participants are actively discussing the integral's definition and the implications of the lower limit. Some have proposed using limits to redefine the integral, while others are exploring different substitutions and transformations. There is no explicit consensus yet, but various lines of reasoning are being examined.

Contextual Notes

There is an ongoing discussion about the integral's well-defined nature, particularly concerning the behavior of \(\ln{x}\) as \(x\) approaches zero. Participants are considering the implications of this for the evaluation of the integral.

noob314
Messages
18
Reaction score
0
I need help on this one


[tex] \int_0^{100} \sqrt{x}ln{x}dx[/tex]


I've tried integrating it by parts and ended up with the equation

[(2/3)(x^3/2)(lnx) - (4/9)(x^3/2)] from 0 to 100

However, I can't plug it in because there's no value of ln(0). So, I'm at a loss right now. Any idea on where to go from here?
 
Physics news on Phys.org
[tex]x^{\frac{3}{2}}\ln x = x^{\frac{1}{2}}(x\ln x)[/tex]

[tex]Let ~u = \frac{1}{x}. ~~Then ~\lim_{x\rightarrow0}(x\ln x) = \lim_{u\rightarrow+\infty}\frac{\ln\frac{1}{u}}{u}[/tex]

Or you might try xlnx = ln(xx) and use the limit of xx as x→0+
 
i think the integral is not well defined and you should be considering

[tex]\stackrel{lim}{a \rightarrow 0} \int_a^{100} dx.\sqrt{x}.ln(x)[/tex]
 
Bohrok said:
[tex]x^{\frac{3}{2}}\ln x = x^{\frac{1}{2}}(x\ln x)[/tex]

[tex]Let ~u = \frac{1}{x}. ~~Then ~\lim_{x\rightarrow0}(x\ln x) = \lim_{u\rightarrow+\infty}\frac{\ln\frac{1}{u}}{u}[/tex]

Or you might try xlnx = ln(xx) and use the limit of xx as x→0+

Thanks. That really helped.
 

Similar threads

  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K