Need help trying to integrate a messy function

  • Thread starter Thread starter insane0hflex
  • Start date Start date
  • Tags Tags
    Function Integrate
Click For Summary
SUMMARY

The discussion focuses on evaluating the integral 2*integral from r-b to r of h(x-r+b)b*sqrt(r^2-x^2) dx. The user attempted a substitution method with u = r^2-x^2 but faced difficulties. The solution involves splitting the integral into two parts: 2*integral from r-b to r of (hx/b) * sqrt(r^2 - x^2) dx and 2*integral from r-b to r of (h(b-r)/b) * sqrt(r^2 - x^2) dx. The first part can be solved using the initial substitution, while the second requires a trigonometric substitution.

PREREQUISITES
  • Understanding of integral calculus, specifically integral evaluation techniques.
  • Familiarity with substitution methods in integration.
  • Knowledge of trigonometric substitutions for integrals.
  • Basic concepts of definite integrals and their properties.
NEXT STEPS
  • Study trigonometric substitution techniques for integrals.
  • Practice problems involving definite integrals and substitution methods.
  • Explore advanced integral calculus topics, including integration by parts.
  • Review resources on integral calculus, such as "Calculus: Early Transcendentals" by James Stewart.
USEFUL FOR

Students in calculus courses, particularly those studying integral calculus, as well as educators seeking to clarify integration techniques and methods.

insane0hflex
Messages
7
Reaction score
0

Homework Statement


Evaulate the following integral:
2*integral from r-b to r of h(x-r+b)b*sqrt(r2-x2) dx
or a picture
http://imgur.com/n2PUN

Homework Equations


The Attempt at a Solution



Tried setting u = r^2-x^2, lost after a couple more steps. Nothing seems to cancel out smoothly. For the record, I am in Calc II, and have not learned integral by parts or trig sub.
Heres a webpage I got the integral from http://mathworld.wolfram.com/CylindricalWedge.html
 
Last edited:
Physics news on Phys.org
I assume r, b, and h are constants. If so, split the integral into
2\displaystyle\int\limits_{r-b}^r \dfrac{hx}{b} \sqrt{r^2 - x^2} dx + 2\int\limits_{r-b}^r \frac{h(b-r)}{b} \sqrt{r^2 - x^2} dx

Then the first can be done with the substitution you've tried already, and the second will require a trig substitution.
 
δοτ said:
I assume r, b, and h are constants. If so, split the integral into
2\displaystyle\int\limits_{r-b}^r \dfrac{hx}{b} \sqrt{r^2 - x^2} dx + 2\int\limits_{r-b}^r \frac{h(b-r)}{b} \sqrt{r^2 - x^2} dx

Then the first can be done with the substitution you've tried already, and the second will require a trig substitution.

Thank you, worked it out and will ask the professor tomorrow. Thanks for your help!
 

Similar threads

Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
20
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K