I need help with what seems to be a simple Electric filed question. I want to mak3 sure that the explanation (attempt at a solution) is sound and make sense. Thanks! 1. The problem statement, all variables and given/known data If an electric field of magnitude 150,000 N/C points due north at a certain spot, what is the magnitude and direction of the force that acts on a charge of -12 uC? 2. Relevant equations E = F / q0 3. The attempt at a solution Correct answer: 1.8 N to the south First, we need to determine the magnitude of the force acting on the charge. Multiply the magnitude of the electric field (E) by the magnitude of the test charge (q0). Because the charge is negative, it acts opposite to the direction of the electric field. E = F / q0 Convert to solve for F: F = Eq0 F = (150,000 N/C) × (-12 uC) -- [remember that 1 uC is 1 × 10^-6 C] F = (150,000 N/C) × (-0.000012) F = -1.8 N The negative sign in the answer indicates the direction of the force of the field. F = 1.8 N to the south.