Need help with an Electric Field Question

[KenG3586]

I need help with what seems to be a simple Electric filed question. I want to mak3 sure that the explanation (attempt at a solution) is sound and make sense. Thanks!

1. Homework Statement
If an electric field of magnitude 150,000 N/C points due north at a certain spot, what is the magnitude and direction of the force that acts on a charge of -12 uC?

Homework Equations

E = F / q0

The Attempt at a Solution

Correct answer: 1.8 N to the south

First, we need to determine the magnitude of the force acting on the charge. Multiply the magnitude of the electric field (E) by the magnitude of the test charge (q0). Because the charge is negative, it acts opposite to the direction of the electric field.

E = F / q0
Convert to solve for F:
F = Eq0
F = (150,000 N/C) × (-12 uC) -- [remember that 1 uC is 1 × 10^-6 C]
F = (150,000 N/C) × (-0.000012)
F = -1.8 N
The negative sign in the answer indicates the direction of the force of the field.
F = 1.8 N to the south.

 

[BvU]

Hello Ken, !

True enough. Good posting. There's no question ?

[edit] Ah, you want a stamp "Approved by PF!"

Unfortunately, those stamps don't exist (they wouldn't really have any value: teachers are almost above the law).
But if they would exist, you sure would be the first in line to get your work stamped thay way